August 21: Permutation PPT Combination PPT
Assignment: From the Auxiliary text: Pg. 634: 3, 9 – 25 odd, 35 - 39, 43, 46, 55 - 81 odd, 87 - 90
August 22: Pascal's Triangle Mathphile video https://www.youtube.com/watch?v=0iMtlus-afo
Part of a Ted Talk video https://www.youtube.com/watch?v=XMriWTvPXHI
Assignment: From the Auxiliary text: Pg. 624: 9, 21, 37, 51, 53, 59, 61, 67, 69, 107
Work on Probability Worksheet
August 23: Continue to work on the probability worksheet and
From the auxiliary text: Pg. 645: Vocab 1 - 8, 3, 5, 6, 9, 13, 18, 21, 24, 34, 37, 41 - 42, 46, 49 - 51, 55,
57* Make the graph of the probability distribution, 60, 63
Answers to the probability worksheet: 1) 125 2) 8,000,000 3) 100,000 4) 720 5) 3360
6) 44,352 7) 315 8) 21,700 9) 126 10) 120 11) 20
August 24: Math Award Learning Task Math Award Learning Task Answers
Answers to the Probability Problems on the Back
August 25: "And You Believed That?" Task Possible Answers to Task
August 28: Today First and Second periods used studentdesmos.com to complete the "[Copy of] Empirical Rule" task.
First period used login code T557N
and second period used login code CUUFA. Feel free to continue working on this tonight.
Third Period completed the "Empirical Rule Learning Task".
The homework assignment for all classes is to download and complete the Testing Task.
August 29: Today we collected the data for the testing task and here it is: Test Task Data More Answers:
6) (P(0) + P(1) + P(2) + P(3) +P(4))/(2^20) = .0059 b) P(10)/(2^20) = .1762 c) (P(9) + P(10) + P(11))*.5^20 =.4966
d) (P(10) + P(11) + P(12)+ P(13) + P(15) + P(16) + P(17) + P(18) +P(19) + P(20))/(2^20) =.5881
e) (P(15) + P(16) + P(17) + P(18) +P(19) + P(20))*.5^20 =.0207 f) (P(14) + P(15) + P(16) + P(17) + P(18) +P(19) +
P(20))/2^20 =.0577 f) Fail g) Yes
Part 2: 1) Yes, For a situation to be considered as having a binomial distribution, the following must be satisfied:
• Each observation/trial has one of two outcomes. These two outcomes are referred to as “success” or “failure”.
• There are a fixed number of observations/trials. The number of observations/trials is referred to as n.
• The observations/trials must be independent.
• The probability of success, referred to as p, is the same for each observation/trial.
2) a) P(0 correct) = 0.2373 b) P(1 correct) = 0.3955 c) P(2 correct) = 0.2637 d) P(3 correct) = 0.0879
e) P(4 correct) = 0.0146 f) P(5 correct) = 0.0010
3) (Histogram) 4) 1.25 or about 1 5) 0 .0156 6) 0.8965 7) 0.1035 8) 2.5 or, rounded 30% 9) 7.5 or 80% yes
10) 6 – 0.25(4) = 5. You could make a 50%; however, if you guessed one of the 4 correctly (which is expected), then
you would still make a 60%. 11a) 6.25 or 60% 11b) 6.666 or 70% 11c) 7.5 or 80%
Part 3:
September 1: Here are the answers to the Probability Review that you got Friday.